This is what light can have mass and momentum despite having zero rest mass.
Most mathematicians will tell you this: when you multiply zero by infinity, you get a finite result.
Which, you'd think would be a divide-zero error. However, according to most mathematicians, 1/0 isn't just an error- as v--> 0, L--> infinity.
You see, when v=c, Lorentz Factor L=1/sqrt(1-c^2/c^2) =1/sqrt(1-1) =1/0
Light (photons) have been shown to have zero REST mass- meaning that if you weighed a photon using a set of scales travelling at c, you wouldn't measure any mass. However, something very weird happens to the m=(Lorentz factor)m0.
However, in order for momentum to be conserved, mass must also increase with velocity according to the Lorentz factor. m=(m0)/sqrt(1-v^2/c^2)
When a particle has velocity relative to an observer, it was shown through special relativity that time dilates (slows down) according to something called the Lorentz factor, 1/(sqrt(1-v^2/c^2))., where t=(t0)/sqrt(1-v^2/c^2) where t is measured time, t0 is proper time, v is velocity and c is the speed of light.
sentinal-5, I'm sorry but I must beg to differ. The key problem in this discussion has been that people haven't differentiated between rest mass and mass- these are two different things.
Ferne, by definition, matter is anything that has volume AND mass. So yes, matter does neccasarily have to have mass
if anyone tries to contradict that, surely you are saying you can prove Einstein wrong. good luck when the entire scientific community comes smashing through your door.