Guillian, it's still a 3 by 3 of CRAY, they just have gaps in-between.
well I guess it's going to be 3^((no.ofCrayOnOneSide+2)*(no.ofCrayOnOtherSide+2)-(no.ofCrayOnOneSide)*(no.ofCrayOnOtherSide)) really.
Maybe I'll find a formula for combinations with grid size... when I can be bothered :p
oh my game crashed after i said that
great explanation, just one thing, that is not a 3x3 square, it is 9x9, a 3x3 square would be 1 pixel of cray
147.800.000.000.000.000.000.000.000.000.0000.000.000 , but using this kinda limits the in/out possibilities because random inputs change the order