MachineMan
MachineMan
1 / 1
2nd September
2nd September
I used LCRY, both decoed and non-decoed, so that one can't argue "you didn't use perfect white".

Comments

  • MachineMan
    MachineMan
    8th November
    *continued from below comment* Your argument "adding white adds red, making it not cyan" proves my point, because, again, if cyan was a type of blue it would mix with red to make magenta, not white, so yes I am right. See comments of ID:3069171
  • MachineMan
    MachineMan
    8th November
    You're quote: "just because cyan is 'brighter than blue, doesn't make it not blue, thats what shades are, so yes, it can be considering blue." You said that cyan is brighter than blue and also that cyan is a shade of blue; brighter and lighter are the same thing, which means you said that cyan is a lighter shade of blue. I fixed the way you spelled 'just' by the way.
  • Qemmen
    Qemmen
    12th October
    i didn't say "lighter shade of blue" i said "shade of blue", also, adding white adds red, making it not cyan, so no, you're wrong.
  • MachineMan
    MachineMan
    22nd September
    You said in the comments of ID:3069171 that cyan was a lighter shade of blue; if that was true, blue and white would make cyan and, evidently, it doesn't.
  • Qemmen
    Qemmen
    7th September
    if you add white to blue, it wouldn't make cyan, it would make a light blue, because cyan doesn't need red, also, adding white and cyan would just bleach it, so no, this isn't proof. -1