The Powder Toy

Geometery Help!

  • nmd     26th Jun 2011 Member 0 Permalink
    I need some help. There is a triangle with each side that measures 18 inches that's circumscribed. I need to find the area of both the triangle and the circle. But here's the problem, when I figured out the area of the triangle using .5bh, It didn't equal the area of the triangle when I used .25(s^2)3 . Is it something I'm doing, or something that's suppose to happen? Thanks in advance!

  • vanquish349     26th Jun 2011 Member 0 Permalink
    what?
  • pilojo     26th Jun 2011 Member 0 Permalink
    @vanquish349 (View Post)
    Don't respond if you have nothing useful to say. This is considered spam.
  • nmd     26th Jun 2011 Member 0 Permalink
    Their are 2 ways to find the area of a triangle. half the base times hight, and (for equalteral triangles) fourth side squared radical 3. but when I tried to find the area of the triangle using both formulas, I get different answers. Why?
  • vanquish349     26th Jun 2011 Member 0 Permalink
    @pilojo (View Post)
    no i mean i am confused with his question

    edit: yeah i understand what you are saying but where did the circle come from
    Edited by vanquish349, 2011-06-24 16:20:48
  • nmd     26th Jun 2011 Member 0 Permalink
    The original problem includes a circle, but I can figure that out.
  • MasterMind555     26th Jun 2011 Member 0 Permalink
    @nmd (View Post)
    Half of their base Times Height Times Two
    You're splitting the triangle into 2 Rectangle Triangles.
  • nmd     26th Jun 2011 Member 0 Permalink
    I still get 2 different answers
  • pilojo     26th Jun 2011 Member 0 Permalink
    @MasterMind555 (View Post)
    So 0.5bx2h

    Either way, you're probably making a mistake in one of the formulas you're using.
    Edited by pilojo, 2011-06-24 16:27:51
  • nmd     26th Jun 2011 Member 0 Permalink
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